Calculus for Economics, Exercises (Dec. 04,2017)
- I
- Let $p,q,I>0$. We maximize the utility function
$$
u(x,y)=x^{\frac 13}y^{\frac 23}
$$
subject to the budget constraint
$$
I-px-qy=0
$$
Find the stationary point and show it the maximal point.
- II
-
Let $p,q,I>0$. We maximize the utility function
$$
u(x,y)=\frac 13\log x+\frac 23\log y
$$
subject to the budget constraint
$$
I-px-qy=0
$$
Find the stationary point and show it the maximal point.
- III
- We optimize the function
$$z=x+y$$
subject to the constraint
$$
x^2+2y^2-24=0
$$
Find the stationary points and check if they are maximal or minimal.
- IV
- We optimize the functionn
$$z=xy$$
subject to the constraint
$$
x^2+y^2-1=0
$$
Find the stationary points and check if they are maximal or minimal.
- V
- We are given a utility function
$u(x,y)=x^{\frac 13}y^{\frac 13}$. We minimize
$f(x,y)=px+qy$ subject to the constraint
\begin{equation*}
u(x,y)=\bar{u}
\end{equation*}
Find the stationary points.
- VI
- The compensated demand functions of Higgs type obtained in V are
denoted by
\begin{equation*}
x^*(p,q,\bar{u}),\ y^*(p,q,\bar{u})
\end{equation*}
We define the minimum const function by
\begin{equation*}
E(p,q,\bar{u})=px^*(p,q,\bar{u})+qy^*(p,q,\bar{u})
\end{equation*}
Then show that the McKenzie's lemma
\begin{equation*}
\frac{\partial E}{\partial p}(p,q,\bar{u})=x^*(p,q,\bar{u}),
\quad
\frac{\partial E}{\partial q}(p,q,\bar{u})=y^*(p,q,\bar{u})
\end{equation*}
holds.
- VII
- We maximize the utility function $u(x,y)=x^{\frac 13}y^{\frac 13}$
subject to the budget constraint
$I-px-qy=0$ to get
\begin{equation}
x(p,q,I)=\frac I{2p},\ y(p,q,I)=\frac I{2q},\
\end{equation}
Moreover we define the indirect utility function
\begin{equation}
v(p,q,I)=u(x(p,q,I),x(p,q,I))
\end{equation}
Then show the following directly.
- (1)
\begin{equation}
x^*(p,q,\bar{u})=x(p,q,E(p,q,\bar{u}))
\end{equation}
- (2)
\begin{equation}
x(p,q,I)=x^*(p,q,v(p,q,I))
\end{equation}
- (3)
\begin{equation}
v(p,q,E(p,q,\bar{u}))=\bar{u}
\end{equation}
- (4)
\begin{equation}
E(p,q,v(p,q,I))=I
\end{equation}
- VIII
- We express the curve $g(x,y):=x^2-xy+y^2-1$
explicitly in a neighborhood of $(1,1)$ by
\begin{equation*}
y=\varphi(x)=\frac {x+\sqrt{4-3x^2}}{2}
\end{equation*}
Find $\varphi''(1)$ by the 1st and second order partial derivatives of $g$.